-5(3b+1)=2(-8b-2)

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Solution for -5(3b+1)=2(-8b-2) equation: 



-5(3b+1)=2(-8b-2)

We move all terms to the left:

-5(3b+1)-(2(-8b-2))=0

We multiply parentheses

-15b-(2(-8b-2))-5=0



We calculate terms in parentheses: -(2(-8b-2)), so:

2(-8b-2)

We multiply parentheses

-16b-4

Back to the equation:

-(-16b-4)



We get rid of parentheses

-15b+16b+4-5=0

We add all the numbers together, and all the variables

b-1=0

We move all terms containing b to the left, all other terms to the right

b=1

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