-5(3b+12)=-3b-5(b+12)

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Solution for -5(3b+12)=-3b-5(b+12) equation: 



-5(3b+12)=-3b-5(b+12)

We move all terms to the left:

-5(3b+12)-(-3b-5(b+12))=0

We multiply parentheses

-15b-(-3b-5(b+12))-60=0



We calculate terms in parentheses: -(-3b-5(b+12)), so:

-3b-5(b+12)

We multiply parentheses

-3b-5b-60

We add all the numbers together, and all the variables

-8b-60

Back to the equation:

-(-8b-60)



We get rid of parentheses

-15b+8b+60-60=0

We add all the numbers together, and all the variables

-7b=0

b=0/-7

b=0

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