-5(3b+2)+(16b-2)=0

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Solution for -5(3b+2)+(16b-2)=0 equation:


Simplifying
-5(3b + 2) + (16b + -2) = 0

Reorder the terms:
-5(2 + 3b) + (16b + -2) = 0
(2 * -5 + 3b * -5) + (16b + -2) = 0
(-10 + -15b) + (16b + -2) = 0

Reorder the terms:
-10 + -15b + (-2 + 16b) = 0

Remove parenthesis around (-2 + 16b)
-10 + -15b + -2 + 16b = 0

Reorder the terms:
-10 + -2 + -15b + 16b = 0

Combine like terms: -10 + -2 = -12
-12 + -15b + 16b = 0

Combine like terms: -15b + 16b = 1b
-12 + 1b = 0

Solving
-12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 0 + 12
1b = 0 + 12

Combine like terms: 0 + 12 = 12
1b = 12

Divide each side by '1'.
b = 12

Simplifying
b = 12

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