-5(3c+4)=5(2c-1)

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Solution for -5(3c+4)=5(2c-1) equation:



-5(3c+4)=5(2c-1)
We move all terms to the left:
-5(3c+4)-(5(2c-1))=0
We multiply parentheses
-15c-(5(2c-1))-20=0
We calculate terms in parentheses: -(5(2c-1)), so:
5(2c-1)
We multiply parentheses
10c-5
Back to the equation:
-(10c-5)
We get rid of parentheses
-15c-10c+5-20=0
We add all the numbers together, and all the variables
-25c-15=0
We move all terms containing c to the left, all other terms to the right
-25c=15
c=15/-25
c=-3/5

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