-5(3p+2)-4(2-p)=3(5p+2)-4

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Solution for -5(3p+2)-4(2-p)=3(5p+2)-4 equation: 



-5(3p+2)-4(2-p)=3(5p+2)-4

We move all terms to the left:

-5(3p+2)-4(2-p)-(3(5p+2)-4)=0

We add all the numbers together, and all the variables

-5(3p+2)-4(-1p+2)-(3(5p+2)-4)=0

We multiply parentheses

-15p+4p-(3(5p+2)-4)-10-8=0



We calculate terms in parentheses: -(3(5p+2)-4), so:

3(5p+2)-4

We multiply parentheses

15p+6-4

We add all the numbers together, and all the variables

15p+2

Back to the equation:

-(15p+2)



We add all the numbers together, and all the variables

-11p-(15p+2)-18=0

We get rid of parentheses

-11p-15p-2-18=0

We add all the numbers together, and all the variables

-26p-20=0

We move all terms containing p to the left, all other terms to the right

-26p=20

p=20/-26

p=-10/13

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