-5(3t-2)+3t=2t-3

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Solution for -5(3t-2)+3t=2t-3 equation: 



-5(3t-2)+3t=2t-3

We move all terms to the left:

-5(3t-2)+3t-(2t-3)=0

We add all the numbers together, and all the variables

3t-5(3t-2)-(2t-3)=0

We multiply parentheses

3t-15t-(2t-3)+10=0

We get rid of parentheses

3t-15t-2t+3+10=0

We add all the numbers together, and all the variables

-14t+13=0

We move all terms containing t to the left, all other terms to the right

-14t=-13

t=-13/-14

t=13/14

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