-5(3u-2)+4u=3(u+1)

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Solution for -5(3u-2)+4u=3(u+1) equation: 



-5(3u-2)+4u=3(u+1)

We move all terms to the left:

-5(3u-2)+4u-(3(u+1))=0

We add all the numbers together, and all the variables

4u-5(3u-2)-(3(u+1))=0

We multiply parentheses

4u-15u-(3(u+1))+10=0



We calculate terms in parentheses: -(3(u+1)), so:

3(u+1)

We multiply parentheses

3u+3

Back to the equation:

-(3u+3)



We add all the numbers together, and all the variables

-11u-(3u+3)+10=0

We get rid of parentheses

-11u-3u-3+10=0

We add all the numbers together, and all the variables

-14u+7=0

We move all terms containing u to the left, all other terms to the right

-14u=-7

u=-7/-14

u=1/2

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