-5(3x-1)=2(x-41)-15

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Solution for -5(3x-1)=2(x-41)-15 equation: 



-5(3x-1)=2(x-41)-15

We move all terms to the left:

-5(3x-1)-(2(x-41)-15)=0

We multiply parentheses

-15x-(2(x-41)-15)+5=0



We calculate terms in parentheses: -(2(x-41)-15), so:

2(x-41)-15

We multiply parentheses

2x-82-15

We add all the numbers together, and all the variables

2x-97

Back to the equation:

-(2x-97)



We get rid of parentheses

-15x-2x+97+5=0

We add all the numbers together, and all the variables

-17x+102=0

We move all terms containing x to the left, all other terms to the right

-17x=-102

x=-102/-17

x=+6

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