-5(3x-1)=2(x-42)-13

Solution for -5(3x-1)=2(x-42)-13 equation:

-5(3x-1)=2(x-42)-13

We move all terms to the left:

-5(3x-1)-(2(x-42)-13)=0

We multiply parentheses

-15x-(2(x-42)-13)+5=0


We calculate terms in parentheses: -(2(x-42)-13), so:

2(x-42)-13

We multiply parentheses

2x-84-13

We add all the numbers together, and all the variables

2x-97

Back to the equation:

-(2x-97)


We get rid of parentheses

-15x-2x+97+5=0

We add all the numbers together, and all the variables

-17x+102=0

We move all terms containing x to the left, all other terms to the right

-17x=-102

x=-102/-17

x=+6