-5(3x-15)=2(x-62)-5

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Solution for -5(3x-15)=2(x-62)-5 equation: 



-5(3x-15)=2(x-62)-5

We move all terms to the left:

-5(3x-15)-(2(x-62)-5)=0

We multiply parentheses

-15x-(2(x-62)-5)+75=0



We calculate terms in parentheses: -(2(x-62)-5), so:

2(x-62)-5

We multiply parentheses

2x-124-5

We add all the numbers together, and all the variables

2x-129

Back to the equation:

-(2x-129)



We get rid of parentheses

-15x-2x+129+75=0

We add all the numbers together, and all the variables

-17x+204=0

We move all terms containing x to the left, all other terms to the right

-17x=-204

x=-204/-17

x=+12

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