-5(3x-19)=2(x-2)-3

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Solution for -5(3x-19)=2(x-2)-3 equation: 



-5(3x-19)=2(x-2)-3

We move all terms to the left:

-5(3x-19)-(2(x-2)-3)=0

We multiply parentheses

-15x-(2(x-2)-3)+95=0



We calculate terms in parentheses: -(2(x-2)-3), so:

2(x-2)-3

We multiply parentheses

2x-4-3

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We get rid of parentheses

-15x-2x+7+95=0

We add all the numbers together, and all the variables

-17x+102=0

We move all terms containing x to the left, all other terms to the right

-17x=-102

x=-102/-17

x=+6

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