-5(3x-2)=3(1-4x)+12

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Solution for -5(3x-2)=3(1-4x)+12 equation: 



-5(3x-2)=3(1-4x)+12

We move all terms to the left:

-5(3x-2)-(3(1-4x)+12)=0

We add all the numbers together, and all the variables

-5(3x-2)-(3(-4x+1)+12)=0

We multiply parentheses

-15x-(3(-4x+1)+12)+10=0



We calculate terms in parentheses: -(3(-4x+1)+12), so:

3(-4x+1)+12

We multiply parentheses

-12x+3+12

We add all the numbers together, and all the variables

-12x+15

Back to the equation:

-(-12x+15)



We get rid of parentheses

-15x+12x-15+10=0

We add all the numbers together, and all the variables

-3x-5=0

We move all terms containing x to the left, all other terms to the right

-3x=5

x=5/-3

x=-1+2/3

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