-5(3x-3)+(16x+1)=0

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Solution for -5(3x-3)+(16x+1)=0 equation:


Simplifying
-5(3x + -3) + (16x + 1) = 0

Reorder the terms:
-5(-3 + 3x) + (16x + 1) = 0
(-3 * -5 + 3x * -5) + (16x + 1) = 0
(15 + -15x) + (16x + 1) = 0

Reorder the terms:
15 + -15x + (1 + 16x) = 0

Remove parenthesis around (1 + 16x)
15 + -15x + 1 + 16x = 0

Reorder the terms:
15 + 1 + -15x + 16x = 0

Combine like terms: 15 + 1 = 16
16 + -15x + 16x = 0

Combine like terms: -15x + 16x = 1x
16 + 1x = 0

Solving
16 + 1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 1x = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 1x = 0 + -16
1x = 0 + -16

Combine like terms: 0 + -16 = -16
1x = -16

Divide each side by '1'.
x = -16

Simplifying
x = -16

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