-5(3x-33)=2(x-8)-23

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Solution for -5(3x-33)=2(x-8)-23 equation:



-5(3x-33)=2(x-8)-23
We move all terms to the left:
-5(3x-33)-(2(x-8)-23)=0
We multiply parentheses
-15x-(2(x-8)-23)+165=0
We calculate terms in parentheses: -(2(x-8)-23), so:
2(x-8)-23
We multiply parentheses
2x-16-23
We add all the numbers together, and all the variables
2x-39
Back to the equation:
-(2x-39)
We get rid of parentheses
-15x-2x+39+165=0
We add all the numbers together, and all the variables
-17x+204=0
We move all terms containing x to the left, all other terms to the right
-17x=-204
x=-204/-17
x=+12

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