-5(3x-4)=5(x-4)+40-20x

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Solution for -5(3x-4)=5(x-4)+40-20x equation:


Simplifying
-5(3x + -4) = 5(x + -4) + 40 + -20x

Reorder the terms:
-5(-4 + 3x) = 5(x + -4) + 40 + -20x
(-4 * -5 + 3x * -5) = 5(x + -4) + 40 + -20x
(20 + -15x) = 5(x + -4) + 40 + -20x

Reorder the terms:
20 + -15x = 5(-4 + x) + 40 + -20x
20 + -15x = (-4 * 5 + x * 5) + 40 + -20x
20 + -15x = (-20 + 5x) + 40 + -20x

Reorder the terms:
20 + -15x = -20 + 40 + 5x + -20x

Combine like terms: -20 + 40 = 20
20 + -15x = 20 + 5x + -20x

Combine like terms: 5x + -20x = -15x
20 + -15x = 20 + -15x

Add '-20' to each side of the equation.
20 + -20 + -15x = 20 + -20 + -15x

Combine like terms: 20 + -20 = 0
0 + -15x = 20 + -20 + -15x
-15x = 20 + -20 + -15x

Combine like terms: 20 + -20 = 0
-15x = 0 + -15x
-15x = -15x

Add '15x' to each side of the equation.
-15x + 15x = -15x + 15x

Combine like terms: -15x + 15x = 0
0 = -15x + 15x

Combine like terms: -15x + 15x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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