-5(3x-4x)=-6+20x-9

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Solution for -5(3x-4x)=-6+20x-9 equation: 



-5(3x-4x)=-6+20x-9

We move all terms to the left:

-5(3x-4x)-(-6+20x-9)=0

We add all the numbers together, and all the variables

-5(-1x)-(20x-15)=0

We multiply parentheses

5x-(20x-15)=0

We get rid of parentheses

5x-20x+15=0

We add all the numbers together, and all the variables

-15x+15=0

We move all terms containing x to the left, all other terms to the right

-15x=-15

x=-15/-15

x=1

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