-5(3x-5)+x=4(x+4)

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Solution for -5(3x-5)+x=4(x+4) equation: 



-5(3x-5)+x=4(x+4)

We move all terms to the left:

-5(3x-5)+x-(4(x+4))=0

We add all the numbers together, and all the variables

x-5(3x-5)-(4(x+4))=0

We multiply parentheses

x-15x-(4(x+4))+25=0



We calculate terms in parentheses: -(4(x+4)), so:

4(x+4)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

-14x-(4x+16)+25=0

We get rid of parentheses

-14x-4x-16+25=0

We add all the numbers together, and all the variables

-18x+9=0

We move all terms containing x to the left, all other terms to the right

-18x=-9

x=-9/-18

x=1/2

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