-5(3x-5)=2(x-19)-5

Solution for -5(3x-5)=2(x-19)-5 equation:

-5(3x-5)=2(x-19)-5

We move all terms to the left:

-5(3x-5)-(2(x-19)-5)=0

We multiply parentheses

-15x-(2(x-19)-5)+25=0


We calculate terms in parentheses: -(2(x-19)-5), so:

2(x-19)-5

We multiply parentheses

2x-38-5

We add all the numbers together, and all the variables

2x-43

Back to the equation:

-(2x-43)


We get rid of parentheses

-15x-2x+43+25=0

We add all the numbers together, and all the variables

-17x+68=0

We move all terms containing x to the left, all other terms to the right

-17x=-68

x=-68/-17

x=+4