-5(3x-5)=2(x-4)-35

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Solution for -5(3x-5)=2(x-4)-35 equation:



-5(3x-5)=2(x-4)-35
We move all terms to the left:
-5(3x-5)-(2(x-4)-35)=0
We multiply parentheses
-15x-(2(x-4)-35)+25=0
We calculate terms in parentheses: -(2(x-4)-35), so:
2(x-4)-35
We multiply parentheses
2x-8-35
We add all the numbers together, and all the variables
2x-43
Back to the equation:
-(2x-43)
We get rid of parentheses
-15x-2x+43+25=0
We add all the numbers together, and all the variables
-17x+68=0
We move all terms containing x to the left, all other terms to the right
-17x=-68
x=-68/-17
x=+4

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