-5(3x-9)=3x+8(2x+1)-31

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Solution for -5(3x-9)=3x+8(2x+1)-31 equation:



-5(3x-9)=3x+8(2x+1)-31
We move all terms to the left:
-5(3x-9)-(3x+8(2x+1)-31)=0
We multiply parentheses
-15x-(3x+8(2x+1)-31)+45=0
We calculate terms in parentheses: -(3x+8(2x+1)-31), so:
3x+8(2x+1)-31
We multiply parentheses
3x+16x+8-31
We add all the numbers together, and all the variables
19x-23
Back to the equation:
-(19x-23)
We get rid of parentheses
-15x-19x+23+45=0
We add all the numbers together, and all the variables
-34x+68=0
We move all terms containing x to the left, all other terms to the right
-34x=-68
x=-68/-34
x=+2

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