-5(3x-9)=3x+8(2x+1)-31

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Solution for -5(3x-9)=3x+8(2x+1)-31 equation: 



-5(3x-9)=3x+8(2x+1)-31

We move all terms to the left:

-5(3x-9)-(3x+8(2x+1)-31)=0

We multiply parentheses

-15x-(3x+8(2x+1)-31)+45=0



We calculate terms in parentheses: -(3x+8(2x+1)-31), so:

3x+8(2x+1)-31

We multiply parentheses

3x+16x+8-31

We add all the numbers together, and all the variables

19x-23

Back to the equation:

-(19x-23)



We get rid of parentheses

-15x-19x+23+45=0

We add all the numbers together, and all the variables

-34x+68=0

We move all terms containing x to the left, all other terms to the right

-34x=-68

x=-68/-34

x=+2

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