-5(3y+3)-5=-6(y+6)+3y

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Solution for -5(3y+3)-5=-6(y+6)+3y equation: 



-5(3y+3)-5=-6(y+6)+3y

We move all terms to the left:

-5(3y+3)-5-(-6(y+6)+3y)=0

We multiply parentheses

-15y-(-6(y+6)+3y)-15-5=0



We calculate terms in parentheses: -(-6(y+6)+3y), so:

-6(y+6)+3y

We add all the numbers together, and all the variables

3y-6(y+6)

We multiply parentheses

3y-6y-36

We add all the numbers together, and all the variables

-3y-36

Back to the equation:

-(-3y-36)



We add all the numbers together, and all the variables

-15y-(-3y-36)-20=0

We get rid of parentheses

-15y+3y+36-20=0

We add all the numbers together, and all the variables

-12y+16=0

We move all terms containing y to the left, all other terms to the right

-12y=-16

y=-16/-12

y=1+1/3

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