-5(3y+3)-9=-9(y+4)+3y

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Solution for -5(3y+3)-9=-9(y+4)+3y equation: 



-5(3y+3)-9=-9(y+4)+3y

We move all terms to the left:

-5(3y+3)-9-(-9(y+4)+3y)=0

We multiply parentheses

-15y-(-9(y+4)+3y)-15-9=0



We calculate terms in parentheses: -(-9(y+4)+3y), so:

-9(y+4)+3y

We add all the numbers together, and all the variables

3y-9(y+4)

We multiply parentheses

3y-9y-36

We add all the numbers together, and all the variables

-6y-36

Back to the equation:

-(-6y-36)



We add all the numbers together, and all the variables

-15y-(-6y-36)-24=0

We get rid of parentheses

-15y+6y+36-24=0

We add all the numbers together, and all the variables

-9y+12=0

We move all terms containing y to the left, all other terms to the right

-9y=-12

y=-12/-9

y=1+1/3

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