-5(3y+4)-20=-6(y+8)+3y

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Solution for -5(3y+4)-20=-6(y+8)+3y equation: 



-5(3y+4)-20=-6(y+8)+3y

We move all terms to the left:

-5(3y+4)-20-(-6(y+8)+3y)=0

We multiply parentheses

-15y-(-6(y+8)+3y)-20-20=0



We calculate terms in parentheses: -(-6(y+8)+3y), so:

-6(y+8)+3y

We add all the numbers together, and all the variables

3y-6(y+8)

We multiply parentheses

3y-6y-48

We add all the numbers together, and all the variables

-3y-48

Back to the equation:

-(-3y-48)



We add all the numbers together, and all the variables

-15y-(-3y-48)-40=0

We get rid of parentheses

-15y+3y+48-40=0

We add all the numbers together, and all the variables

-12y+8=0

We move all terms containing y to the left, all other terms to the right

-12y=-8

y=-8/-12

y=2/3

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