-5(3y-1)+2y=3(y+5)

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Solution for -5(3y-1)+2y=3(y+5) equation: 



-5(3y-1)+2y=3(y+5)

We move all terms to the left:

-5(3y-1)+2y-(3(y+5))=0

We add all the numbers together, and all the variables

2y-5(3y-1)-(3(y+5))=0

We multiply parentheses

2y-15y-(3(y+5))+5=0



We calculate terms in parentheses: -(3(y+5)), so:

3(y+5)

We multiply parentheses

3y+15

Back to the equation:

-(3y+15)



We add all the numbers together, and all the variables

-13y-(3y+15)+5=0

We get rid of parentheses

-13y-3y-15+5=0

We add all the numbers together, and all the variables

-16y-10=0

We move all terms containing y to the left, all other terms to the right

-16y=10

y=10/-16

y=-5/8

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