-5(3y-10)-y=-2(y-3)

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Solution for -5(3y-10)-y=-2(y-3) equation: 



-5(3y-10)-y=-2(y-3)

We move all terms to the left:

-5(3y-10)-y-(-2(y-3))=0

We add all the numbers together, and all the variables

-1y-5(3y-10)-(-2(y-3))=0

We multiply parentheses

-1y-15y-(-2(y-3))+50=0



We calculate terms in parentheses: -(-2(y-3)), so:

-2(y-3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)



We add all the numbers together, and all the variables

-16y-(-2y+6)+50=0

We get rid of parentheses

-16y+2y-6+50=0

We add all the numbers together, and all the variables

-14y+44=0

We move all terms containing y to the left, all other terms to the right

-14y=-44

y=-44/-14

y=3+1/7

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