-5(3y-10)-y=-3(y-4)

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Solution for -5(3y-10)-y=-3(y-4) equation: 



-5(3y-10)-y=-3(y-4)

We move all terms to the left:

-5(3y-10)-y-(-3(y-4))=0

We add all the numbers together, and all the variables

-1y-5(3y-10)-(-3(y-4))=0

We multiply parentheses

-1y-15y-(-3(y-4))+50=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

-16y-(-3y+12)+50=0

We get rid of parentheses

-16y+3y-12+50=0

We add all the numbers together, and all the variables

-13y+38=0

We move all terms containing y to the left, all other terms to the right

-13y=-38

y=-38/-13

y=2+12/13

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