-5(3y-2)-y=-3(y-5)

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Solution for -5(3y-2)-y=-3(y-5) equation: 



-5(3y-2)-y=-3(y-5)

We move all terms to the left:

-5(3y-2)-y-(-3(y-5))=0

We add all the numbers together, and all the variables

-1y-5(3y-2)-(-3(y-5))=0

We multiply parentheses

-1y-15y-(-3(y-5))+10=0



We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We add all the numbers together, and all the variables

-16y-(-3y+15)+10=0

We get rid of parentheses

-16y+3y-15+10=0

We add all the numbers together, and all the variables

-13y-5=0

We move all terms containing y to the left, all other terms to the right

-13y=5

y=5/-13

y=-5/13

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