-5(3y-2)=-2y+4y-7

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Solution for -5(3y-2)=-2y+4y-7 equation: 



-5(3y-2)=-2y+4y-7

We move all terms to the left:

-5(3y-2)-(-2y+4y-7)=0

We add all the numbers together, and all the variables

-5(3y-2)-(2y-7)=0

We multiply parentheses

-15y-(2y-7)+10=0

We get rid of parentheses

-15y-2y+7+10=0

We add all the numbers together, and all the variables

-17y+17=0

We move all terms containing y to the left, all other terms to the right

-17y=-17

y=-17/-17

y=1

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