-5(3y-2)=20y=15

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Solution for -5(3y-2)=20y=15 equation:



-5(3y-2)=20y=15
We move all terms to the left:
-5(3y-2)-(20y)=0
We add all the numbers together, and all the variables
-20y-5(3y-2)=0
We multiply parentheses
-20y-15y+10=0
We add all the numbers together, and all the variables
-35y+10=0
We move all terms containing y to the left, all other terms to the right
-35y=-10
y=-10/-35
y=2/7

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