-5(3y-3)+3y=3(y+8)

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Solution for -5(3y-3)+3y=3(y+8) equation: 



-5(3y-3)+3y=3(y+8)

We move all terms to the left:

-5(3y-3)+3y-(3(y+8))=0

We add all the numbers together, and all the variables

3y-5(3y-3)-(3(y+8))=0

We multiply parentheses

3y-15y-(3(y+8))+15=0



We calculate terms in parentheses: -(3(y+8)), so:

3(y+8)

We multiply parentheses

3y+24

Back to the equation:

-(3y+24)



We add all the numbers together, and all the variables

-12y-(3y+24)+15=0

We get rid of parentheses

-12y-3y-24+15=0

We add all the numbers together, and all the variables

-15y-9=0

We move all terms containing y to the left, all other terms to the right

-15y=9

y=9/-15

y=-3/5

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