-5(3y-4)-y=-3(y-4)

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Solution for -5(3y-4)-y=-3(y-4) equation:



-5(3y-4)-y=-3(y-4)
We move all terms to the left:
-5(3y-4)-y-(-3(y-4))=0
We add all the numbers together, and all the variables
-1y-5(3y-4)-(-3(y-4))=0
We multiply parentheses
-1y-15y-(-3(y-4))+20=0
We calculate terms in parentheses: -(-3(y-4)), so:
-3(y-4)
We multiply parentheses
-3y+12
Back to the equation:
-(-3y+12)
We add all the numbers together, and all the variables
-16y-(-3y+12)+20=0
We get rid of parentheses
-16y+3y-12+20=0
We add all the numbers together, and all the variables
-13y+8=0
We move all terms containing y to the left, all other terms to the right
-13y=-8
y=-8/-13
y=8/13

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