-5(3y-8)-y=-4(y-5)

Solution for -5(3y-8)-y=-4(y-5) equation:

-5(3y-8)-y=-4(y-5)

We move all terms to the left:

-5(3y-8)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-5(3y-8)-(-4(y-5))=0

We multiply parentheses

-1y-15y-(-4(y-5))+40=0


We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)


We add all the numbers together, and all the variables

-16y-(-4y+20)+40=0

We get rid of parentheses

-16y+4y-20+40=0

We add all the numbers together, and all the variables

-12y+20=0

We move all terms containing y to the left, all other terms to the right

-12y=-20

y=-20/-12

y=1+2/3