-5(3y-8)=-2(y-2)

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Solution for -5(3y-8)=-2(y-2) equation:



-5(3y-8)=-2(y-2)
We move all terms to the left:
-5(3y-8)-(-2(y-2))=0
We multiply parentheses
-15y-(-2(y-2))+40=0
We calculate terms in parentheses: -(-2(y-2)), so:
-2(y-2)
We multiply parentheses
-2y+4
Back to the equation:
-(-2y+4)
We get rid of parentheses
-15y+2y-4+40=0
We add all the numbers together, and all the variables
-13y+36=0
We move all terms containing y to the left, all other terms to the right
-13y=-36
y=-36/-13
y=2+10/13

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