-5(3y-8)=-2(y-2)

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Solution for -5(3y-8)=-2(y-2) equation: 



-5(3y-8)=-2(y-2)

We move all terms to the left:

-5(3y-8)-(-2(y-2))=0

We multiply parentheses

-15y-(-2(y-2))+40=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

-15y+2y-4+40=0

We add all the numbers together, and all the variables

-13y+36=0

We move all terms containing y to the left, all other terms to the right

-13y=-36

y=-36/-13

y=2+10/13

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