-5(4-3b)6b+5)=-45

Solution for -5(4-3b)6b+5)=-45 equation:

-5(4-3b)6b+5)=-45

We move all terms to the left:

-5(4-3b)6b+5)-(-45)=0

We add all the numbers together, and all the variables

-5(-3b+4)6b+5)-(-45)=0

We add all the numbers together, and all the variables

-5(-3b+4)6b=0

We multiply parentheses

90b^2-120b=0

a = 90; b = -120; c = 0;
Δ = b2-4ac
Δ = -1202-4·90·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-120}{2*90}=\frac{0}{180}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+120}{2*90}=\frac{240}{180}
=1+1/3
$