-5(4b+1)+(21b-2)=0

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Solution for -5(4b+1)+(21b-2)=0 equation:


Simplifying
-5(4b + 1) + (21b + -2) = 0

Reorder the terms:
-5(1 + 4b) + (21b + -2) = 0
(1 * -5 + 4b * -5) + (21b + -2) = 0
(-5 + -20b) + (21b + -2) = 0

Reorder the terms:
-5 + -20b + (-2 + 21b) = 0

Remove parenthesis around (-2 + 21b)
-5 + -20b + -2 + 21b = 0

Reorder the terms:
-5 + -2 + -20b + 21b = 0

Combine like terms: -5 + -2 = -7
-7 + -20b + 21b = 0

Combine like terms: -20b + 21b = 1b
-7 + 1b = 0

Solving
-7 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 1b = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 1b = 0 + 7
1b = 0 + 7

Combine like terms: 0 + 7 = 7
1b = 7

Divide each side by '1'.
b = 7

Simplifying
b = 7

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