-5(4b+3)+(21b-2)=0

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Solution for -5(4b+3)+(21b-2)=0 equation:


Simplifying
-5(4b + 3) + (21b + -2) = 0

Reorder the terms:
-5(3 + 4b) + (21b + -2) = 0
(3 * -5 + 4b * -5) + (21b + -2) = 0
(-15 + -20b) + (21b + -2) = 0

Reorder the terms:
-15 + -20b + (-2 + 21b) = 0

Remove parenthesis around (-2 + 21b)
-15 + -20b + -2 + 21b = 0

Reorder the terms:
-15 + -2 + -20b + 21b = 0

Combine like terms: -15 + -2 = -17
-17 + -20b + 21b = 0

Combine like terms: -20b + 21b = 1b
-17 + 1b = 0

Solving
-17 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 1b = 0 + 17

Combine like terms: -17 + 17 = 0
0 + 1b = 0 + 17
1b = 0 + 17

Combine like terms: 0 + 17 = 17
1b = 17

Divide each side by '1'.
b = 17

Simplifying
b = 17

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