-5(4t-2)+7t=6t-3

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Solution for -5(4t-2)+7t=6t-3 equation: 



-5(4t-2)+7t=6t-3

We move all terms to the left:

-5(4t-2)+7t-(6t-3)=0

We add all the numbers together, and all the variables

7t-5(4t-2)-(6t-3)=0

We multiply parentheses

7t-20t-(6t-3)+10=0

We get rid of parentheses

7t-20t-6t+3+10=0

We add all the numbers together, and all the variables

-19t+13=0

We move all terms containing t to the left, all other terms to the right

-19t=-13

t=-13/-19

t=13/19

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