-5(4u+4)-6u=2(u-4)-3

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Solution for -5(4u+4)-6u=2(u-4)-3 equation: 



-5(4u+4)-6u=2(u-4)-3

We move all terms to the left:

-5(4u+4)-6u-(2(u-4)-3)=0

We add all the numbers together, and all the variables

-6u-5(4u+4)-(2(u-4)-3)=0

We multiply parentheses

-6u-20u-(2(u-4)-3)-20=0



We calculate terms in parentheses: -(2(u-4)-3), so:

2(u-4)-3

We multiply parentheses

2u-8-3

We add all the numbers together, and all the variables

2u-11

Back to the equation:

-(2u-11)



We add all the numbers together, and all the variables

-26u-(2u-11)-20=0

We get rid of parentheses

-26u-2u+11-20=0

We add all the numbers together, and all the variables

-28u-9=0

We move all terms containing u to the left, all other terms to the right

-28u=9

u=9/-28

u=-9/28

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