-5(4y+3)-5=-8(y+5)=4y

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Solution for -5(4y+3)-5=-8(y+5)=4y equation:



-5(4y+3)-5=-8(y+5)=4y
We move all terms to the left:
-5(4y+3)-5-(-8(y+5))=0
We multiply parentheses
-20y-(-8(y+5))-15-5=0
We calculate terms in parentheses: -(-8(y+5)), so:
-8(y+5)
We multiply parentheses
-8y-40
Back to the equation:
-(-8y-40)
We add all the numbers together, and all the variables
-20y-(-8y-40)-20=0
We get rid of parentheses
-20y+8y+40-20=0
We add all the numbers together, and all the variables
-12y+20=0
We move all terms containing y to the left, all other terms to the right
-12y=-20
y=-20/-12
y=1+2/3

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