-5(4y+3)-5=-8(y+5)=4y

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Solution for -5(4y+3)-5=-8(y+5)=4y equation: 



-5(4y+3)-5=-8(y+5)=4y

We move all terms to the left:

-5(4y+3)-5-(-8(y+5))=0

We multiply parentheses

-20y-(-8(y+5))-15-5=0



We calculate terms in parentheses: -(-8(y+5)), so:

-8(y+5)

We multiply parentheses

-8y-40

Back to the equation:

-(-8y-40)



We add all the numbers together, and all the variables

-20y-(-8y-40)-20=0

We get rid of parentheses

-20y+8y+40-20=0

We add all the numbers together, and all the variables

-12y+20=0

We move all terms containing y to the left, all other terms to the right

-12y=-20

y=-20/-12

y=1+2/3

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