-5(4y-10)-y=-3(y-2)

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Solution for -5(4y-10)-y=-3(y-2) equation:



-5(4y-10)-y=-3(y-2)
We move all terms to the left:
-5(4y-10)-y-(-3(y-2))=0
We add all the numbers together, and all the variables
-1y-5(4y-10)-(-3(y-2))=0
We multiply parentheses
-1y-20y-(-3(y-2))+50=0
We calculate terms in parentheses: -(-3(y-2)), so:
-3(y-2)
We multiply parentheses
-3y+6
Back to the equation:
-(-3y+6)
We add all the numbers together, and all the variables
-21y-(-3y+6)+50=0
We get rid of parentheses
-21y+3y-6+50=0
We add all the numbers together, and all the variables
-18y+44=0
We move all terms containing y to the left, all other terms to the right
-18y=-44
y=-44/-18
y=2+4/9

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