-5(4y-10)-y=-3(y-4)

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Solution for -5(4y-10)-y=-3(y-4) equation:



-5(4y-10)-y=-3(y-4)
We move all terms to the left:
-5(4y-10)-y-(-3(y-4))=0
We add all the numbers together, and all the variables
-1y-5(4y-10)-(-3(y-4))=0
We multiply parentheses
-1y-20y-(-3(y-4))+50=0
We calculate terms in parentheses: -(-3(y-4)), so:
-3(y-4)
We multiply parentheses
-3y+12
Back to the equation:
-(-3y+12)
We add all the numbers together, and all the variables
-21y-(-3y+12)+50=0
We get rid of parentheses
-21y+3y-12+50=0
We add all the numbers together, and all the variables
-18y+38=0
We move all terms containing y to the left, all other terms to the right
-18y=-38
y=-38/-18
y=2+1/9

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