-5(4y-3)-y=-4(y-5)

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Solution for -5(4y-3)-y=-4(y-5) equation: 



-5(4y-3)-y=-4(y-5)

We move all terms to the left:

-5(4y-3)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-5(4y-3)-(-4(y-5))=0

We multiply parentheses

-1y-20y-(-4(y-5))+15=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We add all the numbers together, and all the variables

-21y-(-4y+20)+15=0

We get rid of parentheses

-21y+4y-20+15=0

We add all the numbers together, and all the variables

-17y-5=0

We move all terms containing y to the left, all other terms to the right

-17y=5

y=5/-17

y=-5/17

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