-5(4y-7)-y=-2(y-5)

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Solution for -5(4y-7)-y=-2(y-5) equation: 



-5(4y-7)-y=-2(y-5)

We move all terms to the left:

-5(4y-7)-y-(-2(y-5))=0

We add all the numbers together, and all the variables

-1y-5(4y-7)-(-2(y-5))=0

We multiply parentheses

-1y-20y-(-2(y-5))+35=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We add all the numbers together, and all the variables

-21y-(-2y+10)+35=0

We get rid of parentheses

-21y+2y-10+35=0

We add all the numbers together, and all the variables

-19y+25=0

We move all terms containing y to the left, all other terms to the right

-19y=-25

y=-25/-19

y=1+6/19

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