-5(4y-9)-y=-3(y-2)

Solution for -5(4y-9)-y=-3(y-2) equation:

-5(4y-9)-y=-3(y-2)

We move all terms to the left:

-5(4y-9)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-5(4y-9)-(-3(y-2))=0

We multiply parentheses

-1y-20y-(-3(y-2))+45=0


We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)


We add all the numbers together, and all the variables

-21y-(-3y+6)+45=0

We get rid of parentheses

-21y+3y-6+45=0

We add all the numbers together, and all the variables

-18y+39=0

We move all terms containing y to the left, all other terms to the right

-18y=-39

y=-39/-18

y=2+1/6