-5(5y-3)-y=-2(y-2)

Solution for -5(5y-3)-y=-2(y-2) equation:

-5(5y-3)-y=-2(y-2)

We move all terms to the left:

-5(5y-3)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-5(5y-3)-(-2(y-2))=0

We multiply parentheses

-1y-25y-(-2(y-2))+15=0


We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)


We add all the numbers together, and all the variables

-26y-(-2y+4)+15=0

We get rid of parentheses

-26y+2y-4+15=0

We add all the numbers together, and all the variables

-24y+11=0

We move all terms containing y to the left, all other terms to the right

-24y=-11

y=-11/-24

y=11/24