-5(5y-3)-y=4(y-4)

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Solution for -5(5y-3)-y=4(y-4) equation: 



-5(5y-3)-y=4(y-4)

We move all terms to the left:

-5(5y-3)-y-(4(y-4))=0

We add all the numbers together, and all the variables

-1y-5(5y-3)-(4(y-4))=0

We multiply parentheses

-1y-25y-(4(y-4))+15=0



We calculate terms in parentheses: -(4(y-4)), so:

4(y-4)

We multiply parentheses

4y-16

Back to the equation:

-(4y-16)



We add all the numbers together, and all the variables

-26y-(4y-16)+15=0

We get rid of parentheses

-26y-4y+16+15=0

We add all the numbers together, and all the variables

-30y+31=0

We move all terms containing y to the left, all other terms to the right

-30y=-31

y=-31/-30

y=1+1/30

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