-5(5y-4)-y=2(y-4)

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Solution for -5(5y-4)-y=2(y-4) equation:



-5(5y-4)-y=2(y-4)
We move all terms to the left:
-5(5y-4)-y-(2(y-4))=0
We add all the numbers together, and all the variables
-1y-5(5y-4)-(2(y-4))=0
We multiply parentheses
-1y-25y-(2(y-4))+20=0
We calculate terms in parentheses: -(2(y-4)), so:
2(y-4)
We multiply parentheses
2y-8
Back to the equation:
-(2y-8)
We add all the numbers together, and all the variables
-26y-(2y-8)+20=0
We get rid of parentheses
-26y-2y+8+20=0
We add all the numbers together, and all the variables
-28y+28=0
We move all terms containing y to the left, all other terms to the right
-28y=-28
y=-28/-28
y=1

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