-5(6-x)+8=10-7(x+2)

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Solution for -5(6-x)+8=10-7(x+2) equation:



-5(6-x)+8=10-7(x+2)
We move all terms to the left:
-5(6-x)+8-(10-7(x+2))=0
We add all the numbers together, and all the variables
-5(-1x+6)-(10-7(x+2))+8=0
We multiply parentheses
5x-(10-7(x+2))-30+8=0
We calculate terms in parentheses: -(10-7(x+2)), so:
10-7(x+2)
determiningTheFunctionDomain -7(x+2)+10
We multiply parentheses
-7x-14+10
We add all the numbers together, and all the variables
-7x-4
Back to the equation:
-(-7x-4)
We add all the numbers together, and all the variables
5x-(-7x-4)-22=0
We get rid of parentheses
5x+7x+4-22=0
We add all the numbers together, and all the variables
12x-18=0
We move all terms containing x to the left, all other terms to the right
12x=18
x=18/12
x=1+1/2

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