-5(6-x)=9(x+2)-32

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Solution for -5(6-x)=9(x+2)-32 equation: 



-5(6-x)=9(x+2)-32

We move all terms to the left:

-5(6-x)-(9(x+2)-32)=0

We add all the numbers together, and all the variables

-5(-1x+6)-(9(x+2)-32)=0

We multiply parentheses

5x-(9(x+2)-32)-30=0



We calculate terms in parentheses: -(9(x+2)-32), so:

9(x+2)-32

We multiply parentheses

9x+18-32

We add all the numbers together, and all the variables

9x-14

Back to the equation:

-(9x-14)



We get rid of parentheses

5x-9x+14-30=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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