-5(8-2z)+4(7-z)=7(8+z)-3

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Solution for -5(8-2z)+4(7-z)=7(8+z)-3 equation: 



-5(8-2z)+4(7-z)=7(8+z)-3

We move all terms to the left:

-5(8-2z)+4(7-z)-(7(8+z)-3)=0

We add all the numbers together, and all the variables

-5(-2z+8)+4(-1z+7)-(7(z+8)-3)=0

We multiply parentheses

10z-4z-(7(z+8)-3)-40+28=0



We calculate terms in parentheses: -(7(z+8)-3), so:

7(z+8)-3

We multiply parentheses

7z+56-3

We add all the numbers together, and all the variables

7z+53

Back to the equation:

-(7z+53)



We add all the numbers together, and all the variables

6z-(7z+53)-12=0

We get rid of parentheses

6z-7z-53-12=0

We add all the numbers together, and all the variables

-1z-65=0

We move all terms containing z to the left, all other terms to the right

-z=65

z=65/-1

z=-65

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